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※ 引述《kbgarnett (Ice)》之銘言：
: 餓死抬頭
: 剛一個數學問題想了很久想不出來
: 總數13204
: 如果用399、888、1299、2999
: 在總計26次裡
: 可以各幾次總加成13204嗎
: 謝謝
: -----
: Sent from JPTT on my iPhone

用 python 搭配 numpy 暴力解一下:

import numpy as np
import math
from itertools import product

TARGET = 13204
PARTS = [399, 888, 1299, 2999]
upper_bounds = [math.ceil(TARGET / part) for part in PARTS]
candidates = [np.arange(upper_bound) for upper_bound in upper_bounds]
cartesian_products = np.array([prod for prod in product(*candidates)])
inner_products = np.inner(PARTS, cartesian_products)
indices = np.argwhere(inner_products == TARGET)[:, 0]
results = cartesian_products[indices]

print(TARGET, end='')
for result in results:
    print('\n= ', end='')
    for i in range(len(PARTS)):
        print(' +' if i > 0 else '', PARTS[i], '*', result[i], end='')

靠北根本無解啊

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